Given points A(0,0), B(4,0), C(0,2), D(0,0), E(12,0), and F(0,6), which of the following proves that △ABC~△DEF? A) By the Distance Formula, AB=16 and BC=20Also, DE=144 and EF=180.Therefore, ABDE=BCEF=19,and therefore, ΔABC~ΔDEF by SSS~. B) ΔABC and ΔDEF are not similar. C) By the Distance Formula, AB=4, BC=25–√, and CA=2.Also, DE=12, EF=65–√, and FD=6.Therefore, ABDE=BCEF=CAFD=13,and therefore, ΔABC~ΔDEF by SSS~. D) By the Distance Formula, AB=16, BC=20, and CA=4.Also, DE=144, EF=180, and FD=36.Therefore, ABDE=BCEF=CAFD=19,and therefore, ΔABC~ΔDEF by SSS~.

it would to have a graph or something ! but i had this question so its false

step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.