(Literal Equations) Solve each equation or formula for the variable indicated 2/3y + v = x, for y

y = 3/2( x-v)

Step-by-step explanation:

2/3y + v = x

Subtract v from each side

2/3y + v-v = x-v

2/3y = x-v

Multiply each side by 3/2

3/2 *2/3y  =3/2( x-v)

y = 3/2( x-v)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐