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Mathematics, 07.09.2020 03:01 cheerkennedym2594

There are three values of k for which P(x) = x^3 βˆ’ 2x^2 βˆ’ x + 2 divided by (x βˆ’ k) gives a remainder of zero. Find the three values of k.

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There are three values of k for which P(x) = x^3 βˆ’ 2x^2 βˆ’ x + 2 divided by (x βˆ’ k) gives a remainder...
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