This circle and x + 2y= 12 create a system of equations. Find all solutions, if any, of the resulting system
There are no solutions
(0,6) and (12, 0)
(0,5) and (12,0)
(0,5) and (5,0)

There's something wrong with the answer choices.

There are 2 solutions because the line x+2y = 12 and the circle intersect at two locations. One point of intersection is (0,6). So this suggests choice B is the answer; however, the point (12,0) is not a solution.

It works for x+2y = 12 since 12+2(0) = 12. But the point (12,0) is not on the circle. The furthest to the right we go is (6,0).

where are the choices?