Tickets to a school dance are sold 10$ each . The student council spent a total of 400$ on set-up costs for the dance. The school's profit (p) , in dollars , from the dance depends on the number of tickets sold (t)

P(t) = 10t - 400

Step-by-step explanation:

Selling price of each ticket = $10

Cost of setting up the dance= $400

Profit = Revenue - cost

Revenue = price × quantity

Revenue that will maximize profit = 10t  

where t= quantity of tickets that maximises profits

Cost = $400

Profit(t) = Revenue - cost

P(t)= 10t - 40

hmu if you need sumin els

11

step-by-step explanation:

32.50-7.50=25

225/25=11

i believe that the answer is

b. y-1=-2(x-4)

hope this !