A ball is thrown upward with an initial velocity of 64 ft/sec from a height 720 ft. Its height s, in feet, after t seconds is given by s = - 161? + 64+ + 720. After how long will the ball reach the ground?
7200

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees