A car was driven from an initial position of +12m to a final postion of +30m in 5s. What was the velocity?

difference in distance S= 30m-12m=18m.

initial velocity u=0, distance S=1/2at^2 at

a=2S/t^2=2×18/25=36/25=1.44m/s^2..having gotten the acceleration...we can get the velocity

using V^2=U^2+2aS . since u=0

v^2= 2×1.44×18=51.84

V=sqroot51.84

V=7.2m/s( that is the velocity)

step-by-step explanation:

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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