37. Let f(x) = 2x - 4 and g(x) = 3x + 1. Find g(f(x))

6x-11

Step-by-step explanation:

so g(f(x)) means wherever in g(x), you see x, you replace it with f(x)

g(x) = 3x+1

g(f(x)) = 3(2x-4)+1

= 6x-12+1

= 6x-11

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.