Point J is on line segment IK. Given JK = x + 6. IJ = 9, and IK determine the numerical length of JK.
2x,

a² + b²= c²

24² + 7² = c²

c= 25

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²