Which of the following quadratic functions has roots x=3 and x=-1 A)x^2-2x-3
B)x^2-4x+3
C)x^2+4x+3

Option B is correct

Step-by-step explanation:

1. x^2 - 2x - 3 = 0     where x = 3 and 1

=> 3^2 - 2(3) - 3 = 0

=> 9 - 6 - 3 = 0

=> 9 - 9 = 0

=> 0 = 0

=> 1^2 - 2(1) - 3 = 0

=> 1 - 2 -3 = 0

=> 1 - 5 = 0

=> -4 is not equal to 0.

So, Option A is incorrect.

2. x^2 - 4x + 3 = 0

=> 3^2 - 4(3) + 3 = 0

=> 9 - 12 +3 = 0

=> 12 - 12 = 0

=> 0 = 0

1^2 - 4(1) + 3 = 0

=> 1 - 4 + 3 = 0

=> 4 - 4 = 0

=> 0 = 0

So, Option is B Correct.

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.