The Martins keep goats and chickens on their farm. If there are 23 animals with a total of 74 legs, how many of each type of animal are there? Let the number of chickens be c Then the number of goats in terms of c is (23 – c) State in algebraic terms: the total number of legs the chickens have (1)2c the total number of legs the goats have (2)4c Write an algebraic equation in terms of c to represent the total number of animal legs (74 legs) on the farm. (3) 23-c=74 Hence solve the algebraic equation and calculate the number of goats and chickens on the farm.(4)