Find the inverse of the following f(x)=-3x^2+3 X>0

Answer

f^-1(x) =√[(3-x)÷3]

Step-by-step explanation:

y=-3x^2+3

interchange 'y' with 'x'

x=-3y^2+3

make y the subject

3y^2=3-x

divide by '3' both sides

y^2=(3-x)÷3

apply square root both sides

√(y^2)=√[(3-x)÷3]

y=√[(3-x)÷3]

f^-1(x) =√[(3-x)÷3]

the inverse of the given function is

f^-1(x)=√[(3-x)÷3]

4.08%

step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: