I don’t know how to get started please help

  g'(0) < 0 < g(4) < g(2) < g(-2)

Step-by-step explanation:

You get started by reading the question and understanding what it is asking. Here, it wants to know what the relative signs and magnitudes of the slopes are at different points on the curve.

If the curve goes up to the right, the slope (g') is positive. So, the signs of the slopes at -2, 0, 2 and 4 are +, -, +, +, respectively. That tells you right away that ...

  g'(0) < 0

Now, you have to decide which point on the curve has the highest slope. It is fairly easy to see that the slope at x=4 is less than either of the slopes at x=2 or x=-2. The trick is to decide whether the curve is steeper at -2 or at +2.

My call is that g(-2) > g(2) > g(4), so the increasing order is ...

  g'(0) < 0 < g(4) < g(2) < g(-2)

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

step-by-step explanation: