Question 1: Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. Answers: -1/2 + sqaureroot 5, 1/2 + sqaureroot 5, 1 + sqaureroot 5, -1 + sqaureroot 5 Question 2: Identify the zeros of the function f(x) = 2x2 − 4x + 5 using the Quadratic Formula. Answers: 1 + i sqaureroot 6 / 2, 2 + i sqaureroot 6 / 2, 1 + i sqaureroot 6 / 2, -1 + i sqaureroot 6 / 2

1.  1/2 +/-√5

2.  1 +/-  i √6/2.

Step-by-step explanation:

1.  f(x) = 4x^2 - 8x - 1

x = [-(-8) +/-√((-8)^2 - 4*4*-1)] / (2*4)

x =[ 8 +/- √80] / 8

= 1 +/- 4√5/8

= 1 +/- √5/2

= 1/2 +/-√5

2. By a similar method the zeros of the the second equation are:

x = [-(-4) +/- √((-4)^2 - 4*2*5)]  / 4

= 4 +/- √(16 - 40) / 4

= 1 +/- √(-24)/4

= 1 +/- i  √6 * 2 / 4

= 1 +/-  i √6/2.

a is the right answer

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.