Find values of 3sin^2x-2cosx-3=0

Step-by-step explanation:

3 sin²x-2cos x-3=0

3(1-cos² x)-2 cos x-3=0

3-3 cos²x-2 cos x-3=0

-3 cos ²x-2 cos x=0

cos x( -3cos x-2)=0

cos x=0

x=(2n+1)π/2,where n is an integer.

or -3 cos x-2=0

3 cos x=-2

cos x=-2/3

x=cos ^{-1}(-2/3)≈131.81°

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