58. Given the vertices of parallelogram QRST in the standard (x, y) coordinate plane below, what is the area of triangle QRS, in square units?QE4,3)R(2,3)T(-3,-5)S(3,-5) E. 24
G. 28
H. 48
J. 60
K. 80

answer: idk

step-by-step explanation:

probability for j is 1/4

while

a is 1/6

there are no choices to this, can you give us some choices so that i can answer it

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.