Which shows like terms from the expression? 9 + 5 + 7x2 + 3 x2y + 2x2 3 x2y and 2x2 7x2, 3 x2y, and 2x2 9 and 5 2, 3, 5, and 9

9 and 5.

Step-by-step explanation:

So we have the expression:

In order to combine like terms, the variables must be exactly the same: not one less, not one more.

3x²y and 2x² cannot be combined because the first value has a y.

7x², 3x²y, and 2x² also cannot be combined because the second value has a y.

9 and 5 is the only one that can be combined because they are just integers. They can be added to be 14.

2, 3, 5, and 9 cannot be combined because the 2 and the 3 are tied to the variables as coefficients. They are not constants.

To combine like terms, we can combine numbers with the same power and variables.

We are given the equation: 9 + 5 + 7x^2 + 3x^2y + 2x^2

We can combine 9 and 5 because they are whole numbers by themselves.

We can combine 7x^2 and 2x^2 because they are whole numbers that both have a variable (x) and the same power.

We can't combine anything to 3x^2y because no other number has these features.

Best of Luck!

vbbv

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.