(6a - 10) = 12 – (6 - 3a), when b=11
Mathematics, 03.09.2020 04:01 tayymac1998
Solve the equation by inserting the assigned value.
NH
(6a - 10) = 12 – (6 - 3a), when b=11
A = ?
Answers: 1
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Solve the equation by inserting the assigned value.
NH
(6a - 10) = 12 – (6 - 3a), when b=11
(6a - 10) = 12 – (6 - 3a), when b=11
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