step-by-step explanation:
given that there are two triangles j'k'l' and jkl>
the former is got by dilating the second one.
when drawn on a grid, (graph paper) coordinates of vertices of first triangle is
(6,12)j, (9,6)k and (12,9)l
side jk has length = distance between j and k
=![\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)](/tex.php?f=\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5))
side j'k'=distance between j' and k'
=![\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)](/tex.php?f=\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5))
ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.
hence scale factor of 1/3 is used to get j'k'l'from jkl