Rewrite this formula to convert Fahrenheit to Celsius. F= 9/5C + 35

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Could somebody me with this radical simplification?

Eric drove 275 miles in 5 hours. at the same rate how long would it take him to drive 495 miles?