Identify which equation represents a line perpendicular to the given equation 2x+5y=25

y = 5/2x + 5

y = 5/2x - 9.5

Step-by-step explanation:

We need to solve for the y in the expresion of 2x + 5y = 25

now we re-arrenge the factors in the form y = ax + b

y = -2/5x + 5

we reverse "a"

y = 5/2 + a

And now, we use a point in the other formula to solve for a:

original line:

y = 5 - 2/5x

X = 0 then Y = 5

now we solve for the general equation of the perpendicular equation:

If we use a different point we get a different formula:

original line:

y = 5 - 2/5x

X = 5 then Y = 3

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answer: re

step-by-step explanation: idk buddy

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.