The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the width. Find the dimensions.

The dimensions of the rectangle = 60ft by 107ft

Where 60 ft = Width of the playing field

107ft = Length of the playing field

Step-by-step explanation:

A playing field is Rectangular is shape, hence,

The formula for Perimeter of a rectangle = 2(L + W)

P = 334 ft

L = 47 + W

W = W

Hence we input these values in the formula and we have:

334 = 2(47 + W + W)

334 = 2(47 + 2W)

334 = 94 + 4W

334 - 94 = 4W

240 = 4W

W = 240/4

W = 60

There fore, the width of this playing field = 60 ft

The length of this rectangle is calculated as:

47 + W

47 + 60

= 107 ft

The length of this playing field = 107ft

Therefore the dimensions of the rectangle = 60ft by 107ft

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9