If 26.97 ÷ 6.3 is written in long division form as long division set up where 63 is on the outside of the division symbol and 26970 is on the inside so that the divisor is written as a whole number, where should the decimal point be placed in the dividend? Between the 2 and the 6
Between the 6 and the 9
Between the 9 and the 7
Between the 7 and the 0

The decimal point should be placed between digits 9 and 7 in the dividend. i.e the dividend becomes 269.7

Step-by-step explanation:

Dividend = 26.97       [numerator]

Divisor = 6.3               [denominator]

If 26.97 ÷ 6.3 is written in long division form so that the divisor is written as a whole number, we have the following;

(i)First convert the divisor to a whole number by multiplying by 10 i.e

6.3 x 10 = 63

(ii) Since the divisor (denominator) has been multiplied by 10, to make sure the division expression stays the same, we need to multiply the dividend(numerator) too by 10. i.e

26.97 x 10 = 269.7

(iii) The division expression then becomes;

269.7 ÷ 63

Therefore, the decimal point should be placed between digits 9 and 7 in the dividend.

can you give me Brainliest

9 and 7

Step-by-step explanation:

26.6.3 is long division set up 63 is out of the division symbol and 26970.

2nd one in the first row is correct

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.