HELP k+a=500(1). 3k+10a=3,600(2)

Which equation has at least one of its variables with a 1 as a coefficient?

eqn 1. ( k + a = 500 )

Step-by-step explanation:

In eqn. 1 , both 'k' & 'a' have co-efficient as 1. But in eqn. 2 , 'k' has co-efficient as 3 & 'a' has co-efficient as 10.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer