Suppose R is the solid bounded by the plane z=5x, the surface z=x2, and the planes y=0 and y=3. Write an iterated integral in the form below to find the volume of the solid R.

I have attached the complete question.

See 2nd attachment

Step-by-step explanation:

We are told that R is the solid bounded by the plane z = 5x, the surface z = x², and the planes y = 0 and y = 3.

Thus, the region in the xz plane would be defined as;

0 ≤ x ≤ 3 and x² ≤ z ≤ 5x

For the iterated integral for the volume of the solid R, see 2nd attachment.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb