Mathematics, 01.09.2020 19:01 ajcain5597
An object is launched at 19.6 meters per second (m/s) from a 58.8 meter tall platform. The equation for the object's height s at t time seconds after the launch is s(t)=ā4.9t2+19.6t+58.8
s
(
t
)
=
-
4
.
9
t
2
+
19
.
6
t
+
58
.
8
When does the object strike the ground?
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Fa bus driver leaves her first stop by 7: 00 a.m., her route will take less than 37 minutes. if she leaves after 7: 00 a.m., she estimates that the same route will take no less than 42 minutes. which inequality represents the time it takes to drive the route, r?
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An object is launched at 19.6 meters per second (m/s) from a 58.8 meter tall platform. The equation...
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