Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)

The equation of the line is,

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

the equation of a parallel line is : y=-2/5 x -1

Step-by-step explanation:

2x+5y=15

put the equation in the form of y=mx+b

2x+5y=15

5y=15-2x

y=15/5-2/5 x

y=-2/5 x+3

parallel lines has the same slope : m=-2/5

passes through point (-10,3) find b

y=-2/5 x +b

3=-2/5(-10)+b

3=20/5 +b

3=4+b

b=3-4

b=-1

the equation of a parallel line is : y=-2/5 x -1

i dont know i just need points

if im undersanding the question correctly, its organized from 10

step-by-step explanation: