Solve the two following simultaneous equations and find the possible values of x and y.

Step-by-step explanation:

(*) x^2 + y^2 - 2xy = 64

<=> (x - y)^2 = 64

<=> x - y = 8 or x - y = -8

(**) x^2 - y^2 = 40

<=> (x - y)(x + y) = 40

Case 1: x - y = 8

(**) <=> 8(x + y) = 40

<=> x + y = 5

we have: x+y = 5 and x-y = 8

--> x = (5+8)/2 = 6.5

--> y = x - 8 = 6.5 - 8 = -1.5

so (x,y) = (6.5 , -1.5)

Case 2: x - y = -8

(**) <=> -8(x + y) = 40

<=> x + y = -5

we have: x + y = -5 and x - y = -8

--> x = [ (-5) + (-8) ]/2 = -6.5

--> y = -5 - x = -5 + 6.5 = 1.5

so (x,y) = (-6.5 , 1.5)

(x,y) = (6.5 , -1.5) and (-6.5 , 1.5)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)