You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the number of dimes. Is your friend correct? Let d represent the number of dimes An equation that models this situation is =2.80
(I’m so stupid help)

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2            Combine like terms

2.80 = 0.35d + 2                       Subtract 2 from both sides

0.80 = 0.35d                             Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!

0,0

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