On a vertical line segment, point A is located at 50. Point B is located at 104. Point P is a point that divides segment AB in a ratio of 1:5 from A to B. Where is point P located?

Step-by-step explanation:

Let the initial point on the line segment be O. If point A is located at 50 and point B is located at 104, then OA = 50 and OB = 104. Using the vector notation;

AO+OB = AB

(-OA)+OB = AB

-50+104 = AB

AB = 54

If point P divides the segment AB in a ratio 1:5, them AP:PB = 1:5

AP = 54/6

AP = 9

PB = 54-9

PB = 45

Hence the point P is located at 9 units from A and 45 units from B

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb