A building feet tall has a shadow that is feet long. Find the angle of elevation of the sun to the nearest hundredth of a degree.

The angle of elevation of the sun to the nearest hundredth of a degree is 44.07°

Step-by-step explanation:

Here is the complete question:

A building 86.53 feet tall has a shadow that is 89.39 feet long. Find the angle of elevation of the sun to the nearest hundredth of a degree.

Step-by-step explanation:

Please see the attachment below for an illustrative diagram:

From the diagram

/AC/ is the height of the building

/CB/ is the length of the shadow

/AC/ = 86.53 feet

/CB/ 89.39 feet

θ is the angle of elevation

Consider triangle ABC

/AC/ is the opposite

and /CB/ is the adjacent

From

tanθ =

Then,

tanθ =

tanθ =

tanθ = 0.9680

∴θ = tan⁻¹(0.9680)

θ = 44.0686°

θ = 44.07° (to the nearest hundredth of a degree)

Hence, the angle of elevation of the sun to the nearest hundredth of a degree is 44.07°

your answer would be 12

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15