Eight committee members are meeting in a room that has twelve chairs. In how many ways can they sit in the chairs

Step-by-step explanation:

We will use the combination rule to solve this questions since it bothers selection. Combination has to do with selection.

If r objects are to be selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

If there are Eight committee members meeting in a room that has twelve chairs, the number of ways they can sit in the chair can be done in 12C8 number of ways.

12C8 = 12!/(12-8)!8!

12C8 = 12!/4!8!

12C8 = 12*11*10*9*8!/4*3*2*8!

12C8 =  12*11*10*9/4*3*2

12C8 = 11*10*9/2

12C8 = 11*5*9

12C8 = 495

Hence the committee can sit in the chairs in 495 different ways

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.