Chegg How many times should you throw a pair of dice if you want a probabiliry of at least .85 of getting a sum of 7 at least once?

You need to throw the pair of dice 11 times for you to get a probability of at least .85 of getting a sum of 7 at least once.

Step-by-step explanation:

From the information given:

a pair of dice consists of two dice.

if a pair of dice is thrown, the probability of getting 7 Pr(7) =

Pr (7) =

Now, to estimate the probability of getting a sum of 7 at least once,  we have:

Pr'(7)' = 1 - Probability of getting not sum is 7 ( 0.85 )

Pr'(7)' =  1 - 0.85

Pr'(7)' =  0.15

Probability of getting not sum is 7 =

n × ( - 0.18232) = -1.89711

n =

n =

n 11

You need to throw the pair of dice 11 times for you to get a probability of at least .85 of getting a sum of 7 at least once.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068