A cabinet is 6 feet high, 3 feet wide and 2 feet long. The entire outside of the cabinet is being painted, except for the bottom. What is the surface area being painted?

Step-by-step explanation:

The cabinet is rectangular shaped. Using the formula for calculating the surface area of a reactangular bos to solve the problem.

Surface area = 2(LW+WH+LH) where;

L is the length of the cabinet

W is the width of the cabinet

H is the height of the cabinet.

If the entire outside of the cabinet is being painted, except for the bottom, then the surface area of the painted area will be expressed as;

S = LW+2WH+2LH

Given L = 2 feet, W = 3 feet and H = 6 feet

S = 2(3)+2(3*6)+2(2*6)

S = 6+2(18)+2(12)

S = 6+36+24

S = 66 feet²

Hence the surface area of the painted part is 66ft²

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

hi im bob : l

step-by-step explanation: