One number is 7 more 3 times another number. the sum is 75. what is the smaller number

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According to the statement of the question, we can assemble the following system of equation

X = 7 + 3Y i

X + Y = 75 ii

So, multiplying ii by -1 and adding with i

X = 7 + 3Y

- X - Y = - 75

- Y = 7 + 3Y - 75

4Y = 68

Y = 17

for X we will use ii:

X + Y = 75

X + 17 = 75

X = 58

The smaller number is: 17

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step-by-step explanation:

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a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58