What is fifty five plus seventy two divided by three

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42

Because, 55 + 72 = 127. After you should do 3 ÷ 127. The divisor (3) goes into the first digit of the dividend (1), 0 times. Therefore, put 0 on top. Then you should Multiply the divisor by the result in the previous step (3 × 0 = 0) and write that answer below the dividend. After that Subtract the result in the previous step from the first digit of the dividend (1 - 0 = 1) and write the answer below.  Move down the 2nd digit of the dividend in the below. The divisor (3) goes into the bottom number (12), 4 time(s). Therefore, put 4 on top... Subtract the result in the previous step from the number written above it. (12 - 12 = 0) and write the answer at the bottom. Move down the last digit of the dividend in the below. The divisor (3) goes into the bottom number (7), 2 time(s). Therefore put 2 on top, Multiply the divisor by the result in the previous step (3 x 2 = 6) and write the answer at the bottom... Subtract the result in the previous step from the number written above it. (7 - 6 = 1) and write the answer at the bottom.  The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 127 divided by 3 calculated using Long Division is

42 and Remainder 1.

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Hey There!! ~

The answer to this is: 79. Because, First you need to add fiifty five and seventy two which that will be 127 Then, Add fifity five and seventy two Plus, Divide three Then. you should get the answer 79.

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a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.