P2-16p+48=0 Please solve this math problem

( p - 4 ) ( p - 12 ) = 0

Step-by-step explanation:

To factor this equation, let's apply the quadratic formula.

p^2 - 16p + 48 = 0

Let a = 1, b = -16, c = 48

[-b +/- sqrt(b^2 - 4(a)(c))] / 2 (a)

[- (-16) +/- sqrt( (-16)^2 - 4(1)(48)) ] / 2 (1)

= [ 16 +/- sqrt( 256 - 192) ] / 2

= [ 16 +/- sqrt(64) ] / 2

= [16 +/- 8] / 2

p = (16 + 8) / 2 ; p = (16 - 8) / 2

p = 24 / 2  ; p = 8 / 2

p = 12  ;  p = 4

Hence, this equation factors into the following:

( p - 4 ) ( p - 12 ) = 0

Cheers.

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