A gable roof (isosceles triangle-shaped) has a vertical height of 2.1 metres and the ceiling is 10.9 meters from one side to the other. Find the pitch (angle) of the roof.

Step-by-step explanation:

The given values can be mapped to an isosceles .

Side AB = AC

Vertical height, AD = 2.1 m

The distance between one side to the other side of ceiling = 10.9 m

To find:

Pitch (Angle of the roof ) = ?

i.e. or = ? (because it is isosceles triangle, so both will be equal)

Solution:

As is isosceles, so vertical height will divide the side BC in two equal parts

i.e.

In , let us use tangent trigonometric property.

isi

step-by-step explanation:

use that smart brain

(3x-8) or (3x+8)

step-by-step explanation: