Tickets for a concert cost $2 for children, $3 for students, and $4 for adults. Ticket sales totaled $522 and 177 people attended the concert. Twice as many students as adults attended. Find how many of each type of ticket were sold. Assume that everyone who bought a ticket attended the concert.

Children = 51

Adults = 42

Students= 84

Step-by-step explanation:

Children = $2

Students = $3

Adults = $4

Total sales = $522

Total people who attended = 177

Adults =a

Students = s= 2a

Children = c

c+s+a = 177 (1)

2c+3s+4a=522 (2)

Substitute s=2a into the equations

c + 2a + a = 177

c + 3a = 177 (3)

2c + 3(2a) + 4a = 522

2c + 6a + 4a = 522

2c + 10a = 522 (4)

c + 3a = 177 (3)

2c + 10a = 522 (4)

Multiply (3) by 2

2c + 6a = 354 (3b)

2c + 10a = 522

Subtract (3b) from (4)

10a - 6a = 522 - 354

4a = 168

Divide both sides by 4

a= 168/4

= 42

a= 42

s= 2a

= 2(42)

= 84

s= 84

Substitute the value of s and a into (1)

c+s+a = 177 (1)

c + 84 + 42 = 177

c + 126 = 177

c = 177 - 126

= 51

c=51

Children = 51

Adults = 42

Students= 84

equal to

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct