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dave sold 40 tickets for a concert. he sold x tickets at 2$ each and y tickets at 3$ each. he collected 88$. write down two equations connecting x and y. solve these two equations to find how many of each kind of ticket he sold

For total ticket equation use the given: X+Y=40 then, for second equation on prices 2X+3Y=88

So the equations are:

X+Y=40 and 2X+3Y=88

To solve:

take first equation and place x by itself X=(40-Y) then take the equation and place them together:

2(40-Y)+3Y=88 then Foil;

(80-2Y)+3Y=88 Now combine like terms;

3Y-2Y=88-80 ---> Y=8 after place Y=8 in first equation;

X+Y=40 ---> X+8=40 ---> X=32

So the answers are:                                                                                                                       X=32 and Y=8

A little more than you asked but hope this helps :)

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y