Which is an equation of the line passing through ( -2,3) and perpendicular to the line 5x-y=12

y = -1/5x + 2.6

Step-by-step explanation:

Put the equation into slope intercept form:

5x - y = 12

-y = -5x + 12

y = 5x - 12

The slope of a perpendicular line will be the opposite reciprocal.

So, the slope of the new line will be -1/5

Then, plug this slope and the given point into the equation y = mx + b to find b

y = mx + b

3 = -1/5(-2) + b

3 = 0.4 + b

2.6 = b

So, the equation will be y = -1/5x + 2.6

  x + 5y = 13

Step-by-step explanation:

When the equation of the line is given in the form ...

  ax -by = c

The perpendicular line can be written in the form ...

  bx +ay = constant

where "constant" is found by using the given point values for x and y.

Here, your equation will be ...

  x +5y = (-2) +5(3) = 13 . . . . for point (-2, 3)

The perpendicular line through (-2, 3) is x +5y = 13.

-2 is the right