Pls help A video game designer places an anthill at the origin of a coordinate plane. A red ant
leaves the anthill and moves along a straight line to (1, 1), while a black ant leaves the
anthill and moves along a straight line to (1, -1). Next, the red ant moves to (2, 2), while
the black ant moves to (-2,-2). Then the red ant moves to (3, 3), while the black ant
moves to (-3, -3), and so on. Complete the explanation of why the red ant and the black
ant are always the same distance from the anthill,
At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The
red ant's distance from the anthill is . The black ant's coordinates may be written
as (-a, -a) and the black ant's distance from the anthill is . This shows that at
any given moment, both ants are
units from the anthill.

At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The  red ant's distance from the anthill is . The black ant's coordinates may be written  as (-a, -a) and the black ant's distance from the anthill is  . This shows that at  any given moment, both ants are   units from the anthill.

Step-by-step explanation:

Given:

red ant's coordinates written as (a,a)

black ant's coordinates are written  as (-a, -a)

To find:

The distance of red and black ants from anthill

Solution:

Compute the distance of red ant from the anthill using distance formula

d (red ant) =

                 =

                 =

                 =

So distance of red ant from anthill is

Compute the distance of black ant from the anthill using distance formula

d (black ant) =

                    =

                    =

                 =

                 =

So distance of black ant from anthill is

Hence both ants are   units from the anthill.

hope this .

r3t40

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204