Find the equation of a line that is perpendicular to the line -2y+20=8x and passes through the point (7,2).

  8y -2 = 2x

Step-by-step explanation:

The equation of the perpendicular line will have the coefficients of x and y swapped, and one of them negated. The constant can be found by substituting the given point value:

  8y +constant = 2x . . . . coefficients swapped; former y-coefficient negated

  8(2) +constant = 2(7) . . . . . fill in given point values (x, y) = (7, 2)

  constant = 14 -16 = -2 . . . . subtract 16

The equation can be written as ...

  8y -2 = 2x

_____

Additional comment

Personally, I prefer standard form, which has common factors removed from the coefficients, and has the constant separated from the variable terms:

  x -4y = -1

Some like the slope-intercept form better:

  y = 1/4x +1/4

Apparently, your curriculum author doesn't care how the equation of the line is written, so we have answered with the same form that was given.

2 2/3 hours duhh silly

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this