If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth. triangles ABC and ADC in which angle C is a right angle, point D is on segment BC between points B and C, the measure of angle ABD is x degrees, and the measure of angle ADC is y degrees 0.74 units 1.17 units 1.64 units 2.14 units

  1.17 units

Step-by-step explanation:

From the definition of the sine of an angle, you know ...

  sin(45°) = AC/AB = 4/AB   ⇒   AB = 4/sin(45°) ≈ 5.6569

  sin(63°) = AC/AD = 4/AD   ⇒   AD = 4/sin(63°) ≈ 4.4893

Then the difference AB-AD is ...

  AB -AD = 5.6569 -4.4893 = 1.1676

  AB -AD ≈ 1.17 units

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: