1) How would you solve consecutive integers? 2) What happen to the equations when you solve consecutive EVEN integers? 3) What about consecutive ODD integers?

Step-by-step explanation:

1) If the sum of consecutive integers is given, I usually solve the problem by considering the average of those integers: the sum divided by the number of integers. (See link for an example.)

If some other relation is given then quite often a variable is assigned to one of the integers, often the smallest. If they are consecutive, then the others may be n+1, n+2, n+3 and so on.

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2) If they are consecutive even or odd, then they differ by 2 instead of 1: n, n+2, n+4, and so on.

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3) That difference of 2 is the same whether the integers are consecutive even or consecutive odd. The representation used does not change.

Additional comment

In some instances, you need to ensure that the integers are even or odd, so you might use a representation of 2n for an even integer and 2n+1 for an odd integer. This is rarely an issue in consecutive integer problems.

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: