The sum of two numbers is 167. The second number is 29 less than three times the first number. Fine the numbers. The two required numbers are:

49 and 118

Step-by-step explanation:

Let the two numbers be x and y

x+y = 167

y = 3x-29

Substitute into the first equation

x+ 3x-29 = 167

Combine like terms

4x - 29 = 167

add 29 to each side

4x = 167+29

4x = 196

Divide by 4

4x/4 = 196/4

x = 49

x+y = 167

49+y = 167

y = 167-49

y =118

Step-by-step explanation:

Let the first number be

Let the second number be

Applying substitution method.

Combining like terms.

Adding 29 to both sides.

Dividing both sides by 4.

Substituting x = 49 for the second equation.

Multiplying the numbers.

Subtracting.

The two required numbers are 49 and 118.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse