This question has two parts. Use the information to answer Part A and Part B. Information 1 A camp leader buys a book for each of her campers. She spends $7.50 on each book. Question 1 ,begin emphasis, Part A, end emphasis, Which expression can be used to find the amount of money the camp leader spends on b books? Question 1 Answer options with 4 options (A.)7.50 times b (B.) 7.50 plus b (C.)7.50 minus b (D.)7.50 divided by b Question 2 ,begin emphasis, Part B, end emphasis, If the camp leader has 12 campers, how much does she spend on the books? Enter the answer in the box. Question 2 Response area with 1 text input box $

Question 4 of 10 2 points what is the second part of the process of investigating a question using data? a. rephrasing the question o b. describing the data c. collecting the data o d. making an inference submit

1.3.25 question suppose 40​% of all voters voted for a particular candidate. to simulate exit polls regarding whether or not voters voted for this​ candidate, five random samples of size 1010 and five random samples of size 10001000 have been generated using technology using a population proportion of 0.400.40​, with the accompanying results. complete parts a through c below. click the icon to view the simulation results. a. observe how the sample proportions of successes vary around 0.400.40. simulation compared to sample prop simulation compared to sample prop 1 ▾ 6 ▾ greater than 0.40 less than 0.40 equal to 0.40 2 ▾ less than 0.40 greater than 0.40 equal to 0.40 7 ▾ greater than 0.40 less than 0.40 equal to 0.40 3 ▾ greater than 0.40 less than 0.40 equal to 0.40 8 ▾ equal to 0.40 greater than 0.40 less than 0.40 4 ▾ greater than 0.40 equal to 0.40 less than 0.40 9 ▾ less than 0.40 greater than 0.40 equal to 0.40 5 ▾ equal to 0.40 less than 0.40 greater than 0.40 10 ▾ equal to 0.40 greater than 0.40 less than 0.40 click to select your answer(s) and then click check answer. 2 parts remaining clear all check answer

Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. you take samples and find that the 99% confidence interval of what they are sending is 50.00 to 50.36. what conclusion can be made? homework : 5vd. comparing sample confidence intervals with given intervals (links to an external site.)links to an external site. (3: 43) 5dc. confidence intervals in manufacturing, high vs low level of confidence, wide vs narrow (links to an external site.)links to an external site. (docx) the supplier is less accurate than they claimed the supplier products have a lower mean than claimed the supplier is more accurate than they claimed the supplier products have a higher mean than claimed