If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=−16t2+123t. Find the height of the object after 5 seconds.

Height after 5 seconds is 215 ft

Step-by-step explanation:

Given that:

The initial velocity of object which is projected upwards is 123 ft/sec.

Height of the object, h after time t in seconds,  is given as:

Here, t will always be positive, so and will also be positive.

But coefficient of is negative, that means something is subtracted from the positive term .

To find:

Height of object after 5 seconds.

Solution:

Given that seconds.

Let us put the value in the given relation of and :

So, height after 5 seconds is 215 ft.

mx+89b(-98)nb

step-by-step explanation:

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.