What is the area of a rectangle that is \dfrac1{2} 2 1 start fraction, 1, divided by, 2, end fraction of a meter long and \dfrac38 8 3 start fraction, 3, divided by, 8, end fraction of a meter wide?

Step-by-step explanation:

Given

Shape: Rectangle

Required

Determine the area of the rectangle;

Area is calculated as thus;

Substitute values for Length and Width

Hence, the area of the rectangle is

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1