The length of a rectangle is (t – 8) units, and its width is ('+ 11) units. Which expression can represent the area of the rectangle? A 2 - 33 - 88
B. 22 - 33 + 88
C12 + 31 - 88
D I2 +31 +88

Corrected Question:

The length of a rectangle is (t – 8) units, and its width is (t + 11) units. Which expression can represent the area of the rectangle?

t² + 3t - 88

Step-by-step explanation:

Given:

Rectangle of;

length = (t - 8) units

width = (t + 11) units

The area A of a rectangle is given by;

A  = length x width (i)

Substitute the given length and width into equation (i) as follows;

A = (t - 8) x (t + 11)    [expand the brackets]

A = t² -8t + 11t - 88

A = t² + 3t - 88

Therefore, the area is

(t² + 3t - 88) square units

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

source

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form